25x^2-20x+16=0

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Solution for 25x^2-20x+16=0 equation:


Simplifying
25x2 + -20x + 16 = 0

Reorder the terms:
16 + -20x + 25x2 = 0

Solving
16 + -20x + 25x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
25 the coefficient of the squared term: 

Divide each side by '25'.
0.64 + -0.8x + x2 = 0

Move the constant term to the right:

Add '-0.64' to each side of the equation.
0.64 + -0.8x + -0.64 + x2 = 0 + -0.64

Reorder the terms:
0.64 + -0.64 + -0.8x + x2 = 0 + -0.64

Combine like terms: 0.64 + -0.64 = 0.00
0.00 + -0.8x + x2 = 0 + -0.64
-0.8x + x2 = 0 + -0.64

Combine like terms: 0 + -0.64 = -0.64
-0.8x + x2 = -0.64

The x term is -0.8x.  Take half its coefficient (-0.4).
Square it (0.16) and add it to both sides.

Add '0.16' to each side of the equation.
-0.8x + 0.16 + x2 = -0.64 + 0.16

Reorder the terms:
0.16 + -0.8x + x2 = -0.64 + 0.16

Combine like terms: -0.64 + 0.16 = -0.48
0.16 + -0.8x + x2 = -0.48

Factor a perfect square on the left side:
(x + -0.4)(x + -0.4) = -0.48

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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